A) \[-10Q\]
B) \[-100Q\]
C) \[-1000Q\]
D) \[Q\]
Correct Answer: B
Solution :
Number of moles of \[\text{HCl}=100\times 0.1=10\] Number of moles of \[\text{NaOH =100}\times \text{0}\text{.1=10}\] \[NaOH+HCl\xrightarrow{{}}NaCl+{{H}_{2}}O\] \[\because \] when 1 mole of \[\text{NaOH}\] is neutralised by mole of \[\text{HCl,}\] Then, the heat liberated is = Q kcal or \[\Delta H=-Q\,\text{kcal}\] \[\therefore \] 10 moles of \[\text{NaOH}\] are neutralised by 10 moles of \[\text{HCl,}\] Heat liberated, \[\Delta H=-10\times 10\times Q\,\text{kcal}\] \[=-100Q\,\text{kcal}\]You need to login to perform this action.
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