A) zero
B) 300 joule
C) 200 joule
D) 100 joule
Correct Answer: D
Solution :
Work done against gravity \[=mgh\] \[=2\times 10\times 10=200\text{ }joule\] Total work done \[=300joule\] Hence, work done against friction is \[=300-200=100\text{ }joule\]You need to login to perform this action.
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