A) 5\[\Omega \]
B) 7.5\[\Omega \]
C) 20\[\Omega \]
D) 10\[\Omega \]
Correct Answer: D
Solution :
Given circuit is balanced Wheatstone bridge as \[\frac{P}{Q}=\frac{R}{S}\] hence between point MN, resistance \[10\Omega \] is in effective Therefore, equivalent circuits is Equivalent resistance between XY is \[=\frac{(10+10)(10+10)}{(10+10)+(10+10)}\] \[=\frac{20\times 20}{40}=10\Omega \]You need to login to perform this action.
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