A) 400 Hz
B) 300 Hz
C) 200 Hz
D) 100 Hz
Correct Answer: C
Solution :
Using relation \[f=\frac{p}{2l}\sqrt{\frac{T}{m}}\] (Since, string is plucked at 25 cm hence, it will vibrate in two segments\[p=2\]) \[f=\frac{2}{2\times 1}\sqrt{\frac{20}{0.5\times {{10}^{-3}}}}=200Hz\]You need to login to perform this action.
You will be redirected in
3 sec