A) \[\lambda =2\pi A\]
B) \[\lambda =\pi A\]
C) \[\lambda =\pi A/2\]
D) \[\lambda =\pi A/4\]
Correct Answer: C
Solution :
Maximum particle velocity \[{{\upsilon }_{m}}=A\omega =A\times 2\pi f\] (\[\because \] \[c=f\lambda ,\] \[\Rightarrow \] \[f=\frac{c}{\lambda }\]) \[{{\upsilon }_{m}}=\frac{A2\pi c}{\lambda }\] ?..(1) If \[{{\upsilon }_{m}}=4c\], then from equation (1) \[4c=\frac{A2\pi c}{\lambda }\] So, \[\lambda =\frac{\pi A}{2}\]You need to login to perform this action.
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