A) 220 Hz
B) 440 Hz
C) 880 Hz
D) 1760 Hz
Correct Answer: C
Solution :
Fundamental frequency of closed pipe \[n=\frac{v}{4l}=220Hz\] \[\Rightarrow \] \[v=220\times 4l\] If \[\frac{1}{4}\] of the pipe is filled with water then remaining length of air column is \[\frac{3l}{4}\]. Now, fundamental frequency \[=\frac{v}{4\left( \frac{3l}{4} \right)}=\frac{v}{3l}\] and First overtone \[=3\times \]fundamental frequency. \[=3\times \frac{v}{3L}=\frac{3\times 220\times 4l}{3l}\] \[=880Hz\]You need to login to perform this action.
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