A) \[x=\frac{a}{\sqrt{2}}\]
B) \[x=\sqrt{2a}\]
C) \[x=\frac{\sqrt{2a}}{\sqrt{2-1}}\]
D) \[x=\frac{\sqrt{2a}}{\sqrt{2+1}}\]
Correct Answer: C
Solution :
Suppose the Field vanishes at a distance x, we have \[\frac{Kq}{{{x}^{2}}}=\frac{{{K}_{q/2}}}{{{(x-a)}^{2}}}\] or \[2{{(x-a)}^{2}}={{x}^{2}}\] or \[\sqrt{2}(x-a)=x\] or \[(\sqrt{2}-1)x=\sqrt{2}a\] or \[x=\frac{\sqrt{2}a}{\sqrt{2}-1}\]You need to login to perform this action.
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