A) 180V
B) 30V
C) 18V
D) 90V
Correct Answer: B
Solution :
Given system is a spherical capacitor so, capacitance of system, \[C=K\times 4\pi {{\varepsilon }_{0}}\left[ \frac{{{r}_{1}}{{r}_{2}}}{{{r}_{2}}-{{r}_{1}}} \right]\] \[=\frac{6}{9\times {{10}^{9}}}\left[ \frac{9\times 10}{1} \right]\times {{10}^{-2}}=6\times {{10}^{-10}}F\] Now, potential of inner sphere will be equal to potential difference of the capacitor. So, \[V=\frac{q}{C}=\frac{18\times {{10}^{-9}}}{6\times {{10}^{-10}}}=30V\]You need to login to perform this action.
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