A) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}].2N{{H}_{3}}\]
B) \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl.N{{H}_{3}}\]
C) \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}.N{{H}_{3}}\]
D) \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]
Correct Answer: D
Solution :
Formation of two moles of \[AgCl\] shows that \[2C{{l}^{-}}\] ions are ionisable. \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\underset{3\,ions}{\mathop{{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}}}\,+2C{{l}^{-}}\]\[2C{{l}^{-}}+2AgN{{O}_{3}}\xrightarrow{{}}2AgCl+2NO_{3}^{-}\]You need to login to perform this action.
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