A) -8.1V
B) -3.9V
C) -6V
D) -2.1V
Correct Answer: B
Solution :
\[{{E}_{k}}=hv-\phi \] = 6-21 = 3.9 eV Stopping potential \[\frac{{{E}_{k}}}{e}\] \[\text{=-}\frac{\text{3}\text{.9eV}}{\text{e}}\text{=-3}\text{.9V}\]You need to login to perform this action.
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