A) \[1.96\times {{10}^{8}}m/s\]
B) \[2.12\times {{10}^{8}}m/s\]
C) \[3.18\times {{10}^{8}}m/s\]
D) \[3.33\times {{10}^{8}}m/s\]
Correct Answer: B
Solution :
\[\mu =\frac{\sin \,i}{\sin \,r}=\frac{{{v}_{a}}}{{{v}_{m}}}\] or \[\frac{\sin \,{{45}^{0}}}{\sin \,{{30}^{0}}}=\frac{3\times {{10}^{8}}}{{{v}_{m}}}\] \[\therefore \]\[{{v}_{m}}=3\times {{10}^{8}}\times \frac{1/2}{1/\sqrt{2}}\] \[=3\times {{10}^{8}}\times \frac{1}{\sqrt{2}}\] \[=2.12\times {{10}^{8}}m/s\]You need to login to perform this action.
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