A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{2}\]
D) \[\frac{\pi }{6}\]
Correct Answer: C
Solution :
Given, pair of straight lines is \[12{{x}^{2}}+7xy-12{{y}^{2}}-x-7y-1=0\] Here, \[a+b=12+(-12)=0\] Therefore, both lines are perpendicular.You need to login to perform this action.
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