A) \[x-2y+8=0~~~\]
B) \[x-2y+7=0\]
C) \[x-2y+4=0\]
D) \[2x+2y-13=0\]
Correct Answer: A
Solution :
Equation of straight line parallel to \[x-2y+8=0\] is \[x-2y+\lambda =0\] But, it passes through the point \[(0,\,\,4)\]. \[\therefore \] \[0-8+\lambda =0\] \[\Rightarrow \] \[\lambda =8\] Hence, required line is \[x-2y+8=0\]You need to login to perform this action.
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