A) \[9\]
B) \[27\]
C) \[27/2\]
D) \[18\]
Correct Answer: A
Solution :
Given curves are \[y=\sqrt{x},\,2y+3=x.\] \[\therefore \] point of intersection is \[2y+3={{y}^{2}}\] \[\Rightarrow \] \[{{y}^{2}}-2y-3=0\] \[\Rightarrow \] \[{{y}^{2}}-3y+y-3=0\] \[\Rightarrow \] \[y(y-3)+1(y-3)=0\] \[\Rightarrow \] \[(y-3)\,(y+1)=0\] \[\Rightarrow \] \[y=3,-1\] when \[y=3,\] then \[3=\sqrt{x}\Rightarrow x=9\] \[\therefore \] The point of intersection is \[(9,\,3)\]. \[\therefore \] Required bounded areaYou need to login to perform this action.
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