A) \[0\]
B) \[1\]
C) \[2\]
D) \[-2\]
Correct Answer: C
Solution :
Since, \[\Delta \,ABC\] is a right angled triangle at A. \[\therefore \] \[{{b}^{2}}+{{c}^{2}}={{a}^{2}}\] LHS \[=(a+b+c)\,(b+c-a)\] \[={{(b+c)}^{2}}-{{a}^{2}}\] \[={{b}^{2}}+{{c}^{2}}+2bc-{{a}^{2}}\] \[={{a}^{2}}+2bc-{{a}^{2}}\] \[=2bc\] But \[RHS=\lambda bc\] \[\therefore \]\[\lambda =2\]You need to login to perform this action.
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