J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer The total energy of an electron in 4th orbit of hydrogen atom is

    A)  \[-13.6\,\,eV\]         

    B)  \[-3.4\,\,eV\]

    C)  \[-1.51\,\,eV\]        

    D)  \[-0.85\,\,eV\]

    Correct Answer: D

    Solution :

    For hydrogen atom \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}eV\] \[{{E}_{n}}=\frac{-13.6}{{{4}^{2}}}eV\] \[=-0.85\,eV\]

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