A) Remain stationary at origin O
B) Move along positive X-axis
C) Move along negative X-axis
D) Undergo a circular motion in the X-Y plane
Correct Answer: A
Solution :
The particle is released from rest, i.e. \[v=0\]. Force on the particle due to magnetic field \[F=qvB=q(0)B=0\] Therefore, particle remains stationary at the origin.You need to login to perform this action.
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