A) \[1.57\times {{10}^{-21}}\]
B) \[3.14\times {{10}^{-21}}\]
C) \[1.57\times {{10}^{-23}}\]
D) \[3.14\times {{10}^{-23}}\]
Correct Answer: D
Solution :
Current associated with the revolving charged particle \[I=\frac{q\omega }{2\pi }\] Magnetic moment \[M=IA=\frac{q\omega }{2\pi \times \pi {{r}^{2}}}\] \[=\frac{q\omega {{r}^{2}}}{2}=\frac{1\times {{10}^{-19}}\times 2\pi \times {{10}^{16}}\times {{10}^{-20}}}{2}\] \[=\pi \times {{10}^{-39}}\times {{10}^{16}}=3.14\times {{10}^{-23}}\]You need to login to perform this action.
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