A) current through its secondary is about four times that of the current through its primary
B) voltage across its secondary is about four times that of the voltage across its primary
C) voltage across its secondary is about two times that of the voltage across its primary
D) voltage across its secondary is about\[1/(2\sqrt{2})\]times that of the voltage across its primary
Correct Answer: A
Solution :
For a transformer, ratio of voltages in primary and secondary, can be written as \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{{{I}_{2}}}{{{I}_{1}}}\] \[\Rightarrow \] \[\frac{{{I}_{2}}}{{{I}_{1}}}=\frac{4{{N}_{2}}}{{{N}_{2}}}=4\] \[\Rightarrow \] \[{{I}_{2}}=4{{I}_{1}}\]You need to login to perform this action.
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