A) straight line
B) circular
C) helical
D) parabolic
Correct Answer: D
Solution :
Consider a particle of charge q and mass 222 enters a region of uniform electric field E. At any instant t, coordinates are \[x=\frac{1}{2}\times \frac{qE}{m}{{t}^{2}}\] ...(i) and \[y=ut\] ...(ii) From Eqs. (i) and (ii), we get \[x=\frac{1}{2}\times \frac{qE}{m}\times \frac{{{Y}^{2}}}{{{u}^{2}}}\Rightarrow {{y}^{2}}=\left( \frac{2m{{u}^{2}}}{qE} \right)x\] or \[{{y}^{2}}=kx\] where, k = constant This is an equation of a parabola. So, the path of charge particle will be parabola.You need to login to perform this action.
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