A) \[({{x}_{1}},{{y}_{1}})\]
B) \[x{{y}_{1}}+y{{x}_{1}}={{a}^{2}}\]
C) \[{{x}_{1}}+{{y}_{1}}=a\]
D) \[x{{x}_{1}}+y{{y}_{1}}=x_{1}^{2}+y_{1}^{2}\]
Correct Answer: C
Solution :
\[{{(x+2)}^{2}}=2(y-2)\] equation of latus rectum is \[y-2=-\frac{1}{2}\]\[\Rightarrow \] \[y=\frac{3}{2}\]You need to login to perform this action.
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