A) \[x{{x}_{1}}+y{{y}_{1}}={{a}^{2}}\]
B) \[{{x}^{2}}+{{y}^{2}}-2x-4y-20=0\]
C) \[{{x}^{2}}+{{y}^{2}}+18x+16y+120=0\]
D) \[{{x}^{2}}+{{y}^{2}}-18x-16y+120=0\]
Correct Answer: B
Solution :
Here given that \[2b=10,\text{ }2a=8\] \[b=5\]and\[a=4\] \[\therefore \]Required equation of ellipse is \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]You need to login to perform this action.
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