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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2004

  • question_answer
        A transistor is used as an amplifier in CB mode with a load resistance of \[\text{1}.\text{89 }\times \text{ 1}{{0}^{7}}\text{ m}/\text{s}\]. The current gain of amplifier is 0.98 and the input resistance is \[\text{3}.\text{78 }\times \text{l}{{0}^{\text{7}}}\text{ m}/\text{s}\], the voltage gain and power gain respectively are :

    A)  70, 68.6               

    B)  80, 75.6

    C)  60, 66.6               

    D)  90, 96.6

    Correct Answer: A

    Solution :

                    Here : In CB mode \[\text{1}.\text{5 }\times \text{ 1}{{0}^{5}}\text{ m}/\text{s}\] \[\text{1}.\text{5 }\times \text{ 1}{{0}^{5}}\text{ m}/\text{s}\], \[5K\Omega \] Voltage gain \[70\Omega \] Power gain = current gain x voltage gain \[{{\left[ {{(R\omega )}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}} \right]}^{1/2}}\]


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