A) increases with distance
B) is a constant
C) decreases with distance from centre
D) is zero
Correct Answer: B
Solution :
Key Idea: If a charge is taken from one point to another inside a charged spherical shell no work is done. The electric field inside a spherical charge is zero everywhere. Since, \[E=-\frac{dV}{dx}\] \[\therefore \] \[E=0,\Rightarrow \frac{dV}{dx}=0\] \[\Rightarrow \] V = constant. The value of potential at spherical shell is given by \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{K}volt\] Its value is same as that on the surface. Note: Outside the shell both E and V decrease with distance, E decreases rapidly\[\left( \propto \frac{1}{{{r}^{2}}} \right)\]and decreases compactly slowly\[\left( \propto \frac{1}{r} \right)\].You need to login to perform this action.
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