A) 10%
B) 20%
C) 40 %
D) 44 %
Correct Answer: B
Solution :
The time period of a pendulum of length\[l\]is given by \[T=2\pi \sqrt{\frac{L}{g}}\] where g is acceleration due to gravity. \[\therefore \] \[\frac{\Delta T}{T}\times 100=\frac{1}{2}\frac{\Delta l}{l}\times 100\] % increase in\[T=\frac{1}{2}\times %\]increase in length \[=\frac{1}{2}\times 44=22%\approx 20%\]You need to login to perform this action.
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