A) \[\frac{2}{3}A\]
B) \[3A\]
C) \[6\text{ }A\]
D) \[\text{2 }A\]
Correct Answer: D
Solution :
In the given circuit two\[4\,\Omega \]resistors are connected in parallel, this combination is connected in series with\[1\,\Omega \], resistance. \[\therefore \] \[\frac{1}{R}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}\] \[\Rightarrow \] \[R=2\,\Omega \] Also, \[R=2\,\Omega +1\,\Omega =3\Omega \] From Ohms law, \[V=iR\] \[\therefore \] \[i=\frac{V}{R}=\frac{6}{3}=2A\]You need to login to perform this action.
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