A) reduced to zero
B) decreased by a factor of 2
C) increased by a factor of 2
D) unchanged
Correct Answer: C
Solution :
From the equation of continuity, the amount of mass that flows past any cross-section of a pipe has to be the same as the amount of mass that flows past any other cross-section. i.e., \[{{m}_{1}}={{m}_{2}}\] \[\Rightarrow \] \[{{\rho }_{1}}{{A}_{1}}{{v}_{1}}={{\rho }_{2}}{{A}_{2}}{{v}_{2}}\] Given, \[{{\rho }_{1}}={{\rho }_{2}},{{A}_{2}}=\frac{{{A}_{1}}}{2}\] \[\therefore \] \[{{A}_{1}}{{v}_{1}}=\frac{{{A}_{1}}}{2}{{v}_{2}}\] \[\Rightarrow \] \[{{v}_{2}}=2{{v}_{1}}\]You need to login to perform this action.
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