A) [0, 3]
B) \[[-1,\text{ }1]\]
C) [0, 1]
D) \[[-1,\text{ }3]\]
Correct Answer: D
Solution :
Since\[-2\le \sin x-\sqrt{3}\cos x\le 2\] \[\Rightarrow \]\[-1\le \sin x-\sqrt{3}\cos x+1\le 3\] \[\therefore \]Range of\[f(x)=[-1,3]\].You need to login to perform this action.
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