A) [2, 3]
B) [2, 3)
C) [1, 2]
D) [1, 2)
Correct Answer: B
Solution :
The function\[f(x)=\frac{{{\sin }^{-1}}(x-3)}{\sqrt{9-{{x}^{2}}}}\]will be defined, if (I) \[-1\le x(x-3)\le 1\Rightarrow 2\le x\le 4\] ...(i) (II) \[9-{{x}^{2}}>0\Rightarrow -3<x<3\] ...(ii) From relations (i) and (ii), we get \[2\le x<3\] \[\therefore \]Domain of the given function = [2, 3).You need to login to perform this action.
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