A) 0
B) 2
C) 4
D) \[-4\]
Correct Answer: A
Solution :
Since,\[f(x)\]is odd periodic function with period 2. \[\therefore \]\[f(-x)=-f(x)\]and\[f(x+2)=f(x)\] \[\therefore \]\[f(2)=f(0)\]and\[f(-2)=f(-2+2)=f(0)\] Now, \[f(0)=f(-2)=-f(2)=-f(0)\] \[\therefore \]\[2f(0)=0\] \[\Rightarrow \]\[f(0)=0\] \[\therefore \]\[f(4)=f(2)=f(0)=0\]You need to login to perform this action.
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