A) A is orthogonal matrix
B) \[A\]is orthogonal matrix
C) Determinant\[A\equiv 1\]
D) A is not invertible
Correct Answer: D
Solution :
Given that, \[A=\left[ \begin{matrix} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \\ \end{matrix} \right]\] Now \[|A|={{\cos }^{2}}\theta +{{\sin }^{2}}\theta \ne 0,\] \[\therefore \]A is invertible.. Thus option is not correct.You need to login to perform this action.
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