A) 400 K
B) 500 K
C) 273 K
D) 373 K
Correct Answer: B
Solution :
\[X(g)+3Y(g)2Z(g)\] \[\Delta S{}^\circ =2S{}^\circ (Z)-\{S{}^\circ (X)+3S{}^\circ (Y)\}\] \[=2\times 50-\{60+3\times 40\}\] \[=100-180=-80\,J{{K}^{-1}}mo{{l}^{-1}}\] Given \[\Delta H{}^\circ =-40\,kJ=-40,000J\] \[\Delta G{}^\circ =0\] At/equilibrium, \[\Delta G{}^\circ =0\] \[\therefore \] \[\Delta H{}^\circ =T\Delta S{}^\circ \] Or \[T=\frac{\Delta H{}^\circ }{\Delta S{}^\circ }=\frac{40,000}{80}=500K\]You need to login to perform this action.
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