A) 276pm
B) 138pm
C) 552 pm
D) 415 pm
Correct Answer: C
Solution :
\[NaCl\]has fee structure. In fee lattice \[{{r}^{+}}+{{r}^{-}}=\frac{a}{2}\]where a = edge length \[{{r}^{+}}=95pm\text{ }{{r}^{-}}=181pm\] Edge length \[=2{{r}^{+}}+2{{r}^{-}}\] \[=(2\times 95+2\times 181)pm\] \[=90+362=552pm\]You need to login to perform this action.
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