A) a tertiary alcohol
B) a secondary alcohol
C) a primary alcohol
D) not necessarily an alcohol
Correct Answer: C
Solution :
\[{{C}_{3}}{{H}_{8}}O\xrightarrow[oxidation]{vigorous}{{C}_{3}}{{H}_{6}}{{O}_{2}}\] Since the product is having same number of carbon atoms as the starting compound, it should be primary alcohol since secondary alcohol on vigorous oxidation gives acids having lesser number of carbon atom.You need to login to perform this action.
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