A) \[|z|<3\]
B) \[1<|z|<3\]
C) \[|z|>1\]
D) \[|z|<2\]
Correct Answer: A
Solution :
\[\because \]\[{{\log }_{1/2}}\frac{|z{{|}^{2}}+2|z|+4}{2|z{{|}^{2}}+1}<0={{\log }_{1/2}}1\] \[\Rightarrow \] \[\frac{|z{{|}^{2}}+2|z|+4}{2|z{{|}^{2}}+1}<1\] \[(\because base<1)\] \[\Rightarrow \] \[|z{{|}^{2}}-2|z|-3<0\] \[(|z|+1)(|z|-3)<0\] \[\therefore \] \[|z|<3\]You need to login to perform this action.
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