A) \[n\]
B) \[{{n}^{2}}\]
C) \[{{n}^{3}}\]
D) \[{{n}^{4}}\]
Correct Answer: B
Solution :
Since, 7th and 8th tetras are greatest. Then, \[^{n}{{C}_{6}}.{{x}^{6}}{{=}^{n}}{{C}_{7}}.{{x}^{7}}\] \[\Rightarrow \] \[x=\frac{^{n}{{C}_{6}}}{^{n}{{C}_{7}}}=\frac{7}{n-6}\] \[\therefore \] \[{{\left( \frac{7}{x}+6 \right)}^{2}}={{n}^{2}}\]You need to login to perform this action.
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