A) \[8\mu F\]
B) \[120\mu F\]
C) \[\omega \]
D) \[R/2\]
Correct Answer: A
Solution :
The given circuit can also be made in the following way. This is just like Wheatstone bridge. As the bridge is balanced \[[{{m}^{0}}{{L}^{-1}}{{T}^{0}}]\] there will be no effect on \[[{{m}^{0}}{{L}^{0}}{{T}^{-1}}]\]capacitor. Equivalent capacitance in upper arm \[[{{m}^{0}}{{L}^{-1}}{{T}^{-2}}]\] Equivalent capacitance in lower arm \[[{{m}^{0}}{{L}^{0}}{{T}^{0}}]\] Net capacitance \[1.5\mu \]You need to login to perform this action.
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