A) \[\frac{3\omega }{5}\]
B) \[\frac{2\omega }{3}\]
C) \[\mu =\frac{3}{2}\]
D) \[\mu =\frac{4}{3}\]
Correct Answer: D
Solution :
First, we find out the moment of inertia of the disc about the axis passing the centre and normal to through the plane is \[\mu \] So, for first disc, \[W\] Similarly, for second disc, \[\frac{4W}{3}\] Total moment of inertia of the whole system \[\frac{5W}{2}\] \[=\frac{3}{4}M{{R}^{2}}\] According to the conservation of angular momentum \[\sigma =\text{5}.\text{67}\times \text{1}{{0}^{-\text{8}}}\text{W}-{{\text{m}}^{\text{2}}}{{\text{K}}^{\text{-4}}}\] \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\] \[t\]You need to login to perform this action.
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