A) \[zero\]
B) \[1\]
C) \[i\]
D) \[\omega \]
Correct Answer: D
Solution :
Applying \[{{R}_{1}}\to {{R}_{1}}+{{R}_{3}}\], we obtain \[\left| \begin{matrix} 1-i & {{\omega }^{2}}+\omega & {{\omega }^{2}}-1 \\ 1-i & -1 & {{\omega }^{2}}-1 \\ -i & -1+\omega -i & -1 \\ \end{matrix} \right|=0\] \[\because \]\[{{\omega }^{2}}+\omega =-1\]which \[{{R}_{1}}\] and \[{{R}_{2}}\] become identical.You need to login to perform this action.
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