A) \[2\]
B) \[-2\]
C) \[-4\]
D) \[3\]
Correct Answer: B
Solution :
\[\underset{x\to 2}{\mathop{\lim }}\,\frac{x\,\,f(2)-2f(x)}{x-2}\] \[=\underset{x\to 2}{\mathop{\lim }}\,\frac{x\,\,f(2)-2f(2)+2f(2)-2f(x)}{x-2}\] \[=\underset{x\to 2}{\mathop{\lim }}\,\frac{(x-2)f(2)}{x-2}-2\underset{x\to 2}{\mathop{\lim }}\,\frac{f(x)-f(2)}{x-2}\] \[=f(2)-2f(2)\] \[=4-2\times 4=-4\]You need to login to perform this action.
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