A) \[9\,\,V\]
B) \[zero\]
C) \[2\,\,V\]
D) \[4.5\,\,V\]
Correct Answer: B
Solution :
Potential at \[A\] due to charge at\[O\] \[{{V}_{A}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{({{10}^{-3}})}{OA}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{({{10}^{-3}})}{\sqrt{{{(\sqrt{2})}^{2}}}+{{(\sqrt{2})}^{2}}}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{10}^{-3}}}{2}\] Potential at \[B\] due to charge at\[O\] \[{{V}_{B}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{({{10}^{-3}})}{OB}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{({{10}^{-3}})}{2}\] So,\[{{V}_{A}}-{{V}_{B}}=0\]You need to login to perform this action.
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