A) \[1/3\]
B) \[1/2\]
C) \[1/6\]
D) \[1/4\]
Correct Answer: A
Solution :
The distance of centre of mass of new disc from the centre of mass of remaining disc is\[\alpha R\]. Mass of remaining disc\[=M-\frac{M}{4}=\frac{3M}{4}\] \[\therefore \] \[-\frac{3M}{4}\alpha R+\frac{M}{4}R=0\] \[\Rightarrow \] \[\alpha =\frac{1}{3}\]You need to login to perform this action.
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