A) \[\pm 1\]
B) b)\[\pm \frac{1}{3}\]
C) \[\pm \sqrt{5}\]
D) None of these
Correct Answer: C
Solution :
The point on the line where it intersects the curve, we have\[z=0\]. So that, \[\frac{x-2}{3}=\frac{y+1}{2}=\frac{0-1}{-1}\] \[\Rightarrow \] \[\frac{x-2}{3}=1\]and\[\frac{y+1}{2}=1\] \[\Rightarrow \] \[x=5\]and\[y=1\] Putting these values of \[x\] and \[y\] in\[xy={{c}^{2}}\], we get \[{{c}^{2}}=5\] \[\Rightarrow \] \[c=\pm \sqrt{5}\]You need to login to perform this action.
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