A) \[R\]
B) \[R-\{-1\}\]
C) \[(-\infty ,\,\,-1)\]
D) \[(-1,\,\,\infty )\]
Correct Answer: B
Solution :
Let\[f(x)=y\], then\[\frac{1-x}{1+x}=y\] \[\Rightarrow \] \[x=\frac{1-x}{1+y}\] Thus, \[{{f}^{-1}}(y)=\frac{1-x}{1+x}\] Clearly,\[{{f}^{-1}}(x)\] is denned for\[1+x\ne 0\]. Hence, domain of\[{{f}^{-1}}(x)\]is\[R-\{1\}\].You need to login to perform this action.
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