A) \[\frac{{{2}^{n}}}{2!}\]
B) \[n+1\]
C) \[n+2\]
D) \[2n\]
Correct Answer: C
Solution :
We have,\[{{(1-x)}^{-2}}=1+2x+3{{x}^{2}}+...\] \[+(n+1){{x}^{n}}+(n+2){{x}^{n+1}}+...\] \[\therefore \]Coefficient of\[{{x}^{n+1}}\]is\[n+2\].You need to login to perform this action.
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