A) odd function
B) even function
C) neither even nor odd
D) None of the above
Correct Answer: A
Solution :
Let\[\phi (x)=\int_{0}^{x}{(t)dt}\], \[\phi (-x)=\int_{0}^{-x}{f(t)}dt=-\int_{0}^{x}{f(-2)dz}\] (putting\[t=-z\Rightarrow dt=-dz)\] \[=-\int_{0}^{x}{f(t)}dt=\phi (x)\] \[\therefore \,\,\phi (x)\]is an odd function.You need to login to perform this action.
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