A) \[Zn-Hg+HCl\]
B) \[{{I}_{2}}+NaOH\]
C) Fehling?s reagent
D) \[Sn+NaOH\]solution
Correct Answer: B
Solution :
\[C{{H}_{3}}-CH=CH-C{{H}_{2}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]\[\xrightarrow[iodoform\,\,reaction]{{{I}_{2}}+NaOH}C{{H}_{3}}-CH=CH-C{{H}_{2}}-C{{H}_{2}}COOH\]\[+CH{{I}_{3}}\]You need to login to perform this action.
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