A) prop-1-en-2-ol, metamerism
B) prop-1-en-1-ol, tautomerism
C) prop-2-en-2-ol, \[cis\] and trans isomerism
D) prop-2-en-1-ol, tautomerism
Correct Answer: B
Solution :
\[C{{H}_{3}}-C\equiv CH\xrightarrow[1%\,\,HgS{{O}_{4}}]{40%\,\,{{H}_{2}}S{{O}_{4}}}\underset{prop-1-en-2-ol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,\]\[\xrightarrow{Tautomerisation}C{{H}_{3}}COC{{H}_{3}}\]You need to login to perform this action.
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