A) \[(p\to q)\wedge r\]
B) \[(p\to q)\wedge \tilde{\ }r\]
C) \[(p\wedge q)\wedge (p\vee r)\]
D) \[q\to (p\wedge r)\]
Correct Answer: D
Solution :
Since, \[p\]is true and \[q\] is false. \[\therefore \,\,p\to q\]has truth value\[F\]. Statement \[r\] has truth value\[T\]. \[\therefore \,\,(p\to q)\wedge r\] has truth value\[F\]. Also, \[(p\to q)\wedge \tilde{\ }r\]has truth value\[F\]. Now, \[p\wedge q\] has truth value \[F\] and \[p\vee r\] has truth value\[T\]. \[\therefore \]\[(p\wedge q)\wedge (p\wedge q)\]has truth value\[F\]. As, \[p\wedge r\] has truth value\[T\]. Therefore, \[q\to (p\wedge r)\] has truth value\[T\].You need to login to perform this action.
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