A) \[0\]
B) \[-1\]
C) \[1\]
D) None of these
Correct Answer: A
Solution :
Let \[\alpha \] be a real root of the given equation. Then, \[{{\alpha }^{2}}+(a+i)\alpha +b+ic=0\] On equating real and imaginary parts both sides, we get \[{{\alpha }^{2}}+a\alpha +b=0\] ... (i) and \[\alpha +c=0\] ... (ii) On solving Eqs. (i) and (ii), we get \[{{c}^{2}}-ac+b=0\]You need to login to perform this action.
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